Reimplement Oracle NUMBER to/from C++ integer type conversions

The implementation has been moved to the details namespace. Signed and
unsigned 32 bit versions, as well as an unsigned 64 bit version have also
been added.

1 files changed, 0 insertions, 135 deletions

diff --git a/odb/oracle/traits.cxx b/odb/oracle/traits.cxx
index 4bae42d..3e95a00 100644
--- a/odb/oracle/traits.cxx
+++ b/odb/oracle/traits.cxx
@@ -3,139 +3,4 @@
 // copyright : Copyright (c) 2005-2011 Code Synthesis Tools CC
 // license   : GNU GPL v2; see accompanying LICENSE file
 
-#include <cstddef>  // std::size_t
-#include <cmath>    // pow
-#include <deque>
-
 #include <odb/oracle/traits.hxx>
-
-using namespace std;
-
-namespace odb
-{
-  namespace oracle
-  {
-    long long
-    out (unsigned char const* n)
-    {
-      // The first byte specifies the length of the number representation,
-      // including the exponent byte and significant digits but not the length
-      // itself.
-      //
-      int len (n[0]);
-
-      if (len == 1)
-        return 0;
-
-      long long v (0);
-      if (n[1] & 0x80)
-      {
-        // The exponent of a positive number is calculated as n[1] - 193.
-        // The base-100 exponent of the least significant digit can be
-        // calculated as exp - sig - 1, where sig is the number of significant
-        // digits. sig may be calculated as len - 2.
-        //
-        int exp (n[1] - 191 - len);
-
-        for (unsigned char const* m (n + len), *e (n + 1); m > e; --m, ++exp)
-          v += (*m - 1) * pow (100, exp);
-      }
-      else
-      {
-        // The exponent of a negative number is calculated as ~n[1] - 193.
-        // The base-100 exponent of the least significant digit can be
-        // calculated as exp - sig - 1, where sig is the number of significant
-        // digits. sig may be calculated as len - 2.
-        //
-        int exp (~n[1] - 190 - len);
-
-        for (unsigned char const* m (n + len - 1), *e (n + 1); m > e;
-             --m, ++exp)
-          v -= (101 - *m) * pow (100, exp);
-      }
-
-      return v;
-    }
-
-    void
-    in (unsigned char b[22], long long n)
-    {
-      if (n == 0)
-      {
-        b[0] = 1;
-        b[1] = 128;
-
-        return;
-      }
-
-      // @@ Is there some sort of reserve() implementation for deque?
-      //
-      deque<unsigned char> s;
-
-      bool sig (false);
-      size_t c (0);
-      unsigned char exp (0);
-
-      if (n < 0)
-      {
-        // Termination marker for negative numbers.
-        //
-        s.push_front (102);
-
-        while (n != 0)
-        {
-          int v (static_cast<int> (n % 100));
-          sig = sig ? true : v != 0;
-
-          if (sig)
-            s.push_front (static_cast<unsigned char> (101 + v));
-
-          n /= 100;
-          ++c;
-        }
-
-        // The exponent is one less than the number of base 100 digits. It is
-        // inverted for negative values.
-        //
-        exp = static_cast<unsigned char> (~(c + 192));
-      }
-      else
-      {
-        while (n != 0)
-        {
-          int v (static_cast<int> (n % 100));
-          sig = sig ? true : v != 0;
-
-          if (sig)
-            s.push_front (static_cast<unsigned char> (v + 1));
-
-          n /= 100;
-          ++c;
-        }
-
-        // Exponent is one less than the number of base 100 digits.
-        //
-        exp = static_cast<unsigned char> (c + 192);
-      }
-
-      // Set the length.
-      //
-      b[0] = static_cast<unsigned char> (s.size () + 1);
-
-      // Set the exponent.
-      //
-      b[1] = exp;
-
-      // Set the significant digits (big-endian byte order) and the terminator,
-      // if any.
-      //
-      c = 2;
-      while (!s.empty ())
-      {
-        b[i] = s.front ();
-        s.pop_front ();
-        ++c;
-      }
-    }
-  }
-}